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What are the odds against winning seven hands of blackjack in a row? If I play hands of blackjack at $5 a hand at an % house edge how much The number of ways to arrange 3 cards in a 6-deck shoe is combin(,3)=5,,

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What are the odds against winning seven hands of blackjack in a row? If I play hands of blackjack at $5 a hand at an % house edge how much The number of ways to arrange 3 cards in a 6-deck shoe is combin(,3)=5,,

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How many more hands get played for 6-deck vs 2-deck each day (shuffling time included)? Are the counts based upon one player or the average.

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Namely, how many decks that are in the shoe you are playing. Below I SINGLE DECK - BASIC STRATEGY Your Hand vs Dealer's Upcard 8 Double on 5 to 6.

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The basic premise of card counting is that a deck or shoe that is 'rich' in face cards If the dealer receives a poor hand as the original two cards (IE: a point count of 12 to Here again, computer simulations of the many different methods of card you have a running count total of +6, which is a nice advantage to the player.

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This is good advice if you are playing heads up and have simmed this situation and know exactly what to bet on how many hands at each count.

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On the first hand I had a 6 and a 3; the dealer showed a 4. I doubled So much for miracles. Most Awkward Situation I was playing alone at a 6-deck shoe.

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Basic Strategy for 3–6 decks) Action Hand value When Dealer shows Double 11 soft 17 and 18 3 through 6 Soft 15 and 16 4 through 6 Soft 13 and 14 5 or 6 return for an 8-deck shoe is −; the reshuffle return improves to +

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Quick? about hands per shoe/hands per session What is the typical and easiest way to calculate hands per hr in DD and 6 deck? If you know how many cards there are before shuffle time (ie: 75% pen on DD = *

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What are the odds against winning seven hands of blackjack in a row? If I play hands of blackjack at $5 a hand at an % house edge how much The number of ways to arrange 3 cards in a 6-deck shoe is combin(,3)=5,,

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Because the sum of a large number of random variables always will approach a bell curve we can use the central limit theorem to get at the answer. You are forgetting that there are two possible orders, either the ace or the ten can be first. Take another 8 out of the deck. From my section on the house edge we find the standard deviation in blackjack to be 1. Multiply this dot product by the probability from step 2. However there are other ways you get four aces in the same hand, for example the last card might be an 8 or 9. I hope this answers your question. Streaks, such as the dealer drawing a 5 to a 16, are inevitable but not predictable. These expected values consider all the numerous ways the hand can play out. I recently replaced my blackjack appendix 4 with some information about the standard deviation which may help. Determine the probability that the player will resplit to 3 hands. That column seemed to put the mathematics to that "feeling" a player can get. So, the best card for the player is the ace and the best for the dealer is the 5. My question though is what does that really mean? Since this question was submitted, a player held the dice for rolls on May 23, in Atlantic City. Putting aside some minor effects of deck composition, the dealer who pulled a 5 to a 16 the last five times in a row would be just as likely to do it the next time as the dealer who had been busting on 16 for several hours. In general the variation in the mean is inversely proportional to the square root of the number of hands you play. Take the dot product of the probability and expected value over each rank. Or does it mean that on any given loss it is a 1 in chance that it was the first of 8 losses coming my way? If you were to add a card as the dealer you should add a 5, which increases the house edge by 0. It would take about 5 years playing blackjack 40 hours a week before this piece of advice saved the player one unit. Your question however could be rephrased as, "what is the value of the ace, given that the other card is not a ten. I would have to do a computer simulation to consider all the other combinations. The following table displays the results. It depends whether there is a shuffle between the blackjacks. According to my blackjack appendix 9H the expected return of standing is So my hitting you will save 6. Repeat step 3 but multiply by 4 instead of 2, and this time consider getting an 8 as a third card, corresponding to the situation where the player is forced to stop resplitting.

This is a typical question one might encounter in an introductory statistics class. It how many hands in a 6 deck shoe also be the result of progressive betting or mistakes in strategy. When I said the probability of losing 8 hands in win at blackjack every time row how many hands in a 6 deck shoe 1 in I meant that starting with the next hand the probability of losing 8 in a row is 1 in The chances of 8 losses in a row over a session are greater the longer the session.

For how to solve the problem yourself, see my MathProblems. The best play for a billion hands is the best play for one hand. Determine the probability that the player will resplit to 4 hands. Thanks for your kind words. It took me years to get the splitting pairs correct myself. To test the most likely case to favor hitting, 8 decks and only 3 cards, I ran every possible situation through my combinatorial program.

Add values from steps 4, how many hands in a 6 deck shoe, and The hardest part of all this is step 3. This is not even a marginal play. Thanks for the kind words. However if you were going to cheat it would be much better to remove an ace, which increases the house edge by 0. Let n be the number of decks.

All of this assumes flat betting, otherwise the math really gets messy. Besides every once in awhile throwing down a bigger bet just adds to the excitement and for some reason it seems logical that if you have lost a string of hands you are "due" for a win.

In that case, the probability of a win, given a resolved bet, is The probability of winning n hands is a row is 0. It is more a matter of degree, the more you play the more your results will approach the house edge. I have no problem with increasing your bet when you get a lucky feeling.

Cindy of Gambling Tools was very helpful. Here is https://21vek-dance.ru/blackjack/darkstar-blackjack.html I did it. What you have experienced is likely the result of some very bad losing streaks.

The standard deviation of one hand is 1. What is important is that you play your cards right. Multiply dot product from step 11 by probability in step 9. Here is the exact answer for various numbers of decks. When the dealer stands on a soft 17, the dealer will bust about When the dealer hits on a soft 17, the dealer will bust about According to my blackjack appendix 4the probability of a net win is However, if we skip ties, the probability is how many hands in a 6 deck shoe So, the probability of a four wins in a row is 0.

Probability of Blackjack Decks How many hands in a 6 deck shoe 1 4. I know, I know, its some sort of divine intervention betting system I am talking about and no betting system affects the house edge. As I always say all betting systems are equally worthless so flying by the seat of your pants is just as good as flat betting over the long term.

Determine the probability that the player will not get a third eight on either hand. It depends on the number of decks. If I'm playing for fun then I leave the table when I'm not having fun any longer. If the probability of a blackjack is p then the probability of not getting any blackjacks in 10 hands is 1- 1-p For example in a six deck game the answer would be 1- 0.

The probability of this is 1 in 5,, For the probability for any number of throws from 1 toplease see my craps survival tables. There are 24 sevens in the shoe. Repeat step 3 but multiply by 3 instead of 2. You ask a good question for which there is no firm answer.

Resplitting up to four hands is allowed. Steve from Phoenix, AZ. If you want to deviate from the basic strategy here are some borderline plays: 12 against 3, 12 against 4, 13 against 2, 16 against Deviating on these hands will cost you much less. The fewer the decks and the greater the number of cards the more this is true.

If there were a shuffle between hands the probability would increase substantially.

So the probability of winning six in a row is 0. Expected Values for 3-card learn more here Vs. There is no sound bite answer to explain why you should hit.

Unless you are counting cards you have the free will to bet as much as you want. So standing is the marginally better play. There are cards remaining in the two decks and 32 are tens.

From my blackjack appendix 7 we see that each 9 removed from a single deck game increases the house edge by 0. I have a very ugly subroutine full of long formulas I determine using probability trees.

Is it that when I sit down at the table, 1 out of my next playing sessions I can expect to have an 8 hand losing streak? For the non-card counter it may be assumed that the odds are the same in each new round. For each rank determine the probability of that rank, given that the probability of another 8 is zero. Blackjack is not entirely a game of independent trials like roulette, but the deck is not predisposed to run in streaks. Following this rule will result in an extra unit once every hands. Multiply dot product from step 7 by probability in step 5. Go through all ranks, except 8, subtract that card from the deck, play out a hand with that card and an 8, determine the expected value, and multiply by 2. According to my blackjack appendix 4 , the probability of an overall win in blackjack is I'm going to assume you wish to ignore ties for purposes of the streak. Any basic statistics book should have a standard normal table which will give the Z statistic of 0.